x^2-12x+36=(16)^2

Solution for x^2-12x+36=(16)^2 equation:

x^2-12x+36=(16)^2

We move all terms to the left:

x^2-12x+36-((16)^2)=0

determiningTheFunctionDomain
x^2-12x+36-16^2=0

We add all the numbers together, and all the variables

x^2-12x-220=0

a = 1; b = -12; c = -220;
Δ = b2-4ac
Δ = -122-4·1·(-220)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-32}{2*1}=\frac{-20}{2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+32}{2*1}=\frac{44}{2}
=22
$